See below. We need to differentiate f (x) to find the gradient function. With this we can find the gradient at each given point and consequently be able to find the equations of the two lines.

Explanation: We differentiate to find a gradient, often differentiating with respect to time as many variables are plotted graphically against time. Gradients are very useful for discovering the …

Now the expression is simplified, differentiating to find the gradient is easy is much easier. (Multiply the whole thing by the power and then subtract 1 from the power to differentiate.)

Jan 29, 2017 · Tangent Equation: y = x+1 Normal Equation: \\ y = -x+1 The gradient of the tangent to a curve at any particular point is given by the derivative of the curve at that point. The …

These will define a unique point. It is unimportant which ones you choose. I will use: Line AB passing through C Line AC passing through B For AB First find the gradient of this line …

Taking AC as the base, we now find the gradient of this line segment, then we find the equation of the line. We then find the equation of the line perpendicular to this passing through the vertex B.

Explanation: Find the gradient #color (pink)m# of the line by using the formula # (y_2-y_1)/ (x_2-x_1)#.

The slope represents the change in y for a unit change in x, and might also be called the gradient of a line. It gives us a measure of how steep the line is. We can see changing x will give a …

Mar 4, 2016 · To find the equation in the form y = mx + c , where m represents the gradient and c, the y-intercept. The value of f' (2) will give m and f (2) will assist in finding c.

May 5, 2017 · The gradient of the tangent to a curve at any particular point is given by the derivative of the curve at that point. The normal is perpendicular to the tangent so the product …